Base | Representation |
---|---|
bin | 11101010110010101… |
… | …010111010011000101 |
3 | 10000100012200001010202 |
4 | 131112111113103011 |
5 | 1004014340241401 |
6 | 22251005300245 |
7 | 2163632611640 |
oct | 352625272305 |
9 | 100305601122 |
10 | 31513212101 |
11 | 12401428748 |
12 | 6135864685 |
13 | 2c82a31c87 |
14 | 174d3caa57 |
15 | c468d306b |
hex | 7565574c5 |
31513212101 has 64 divisors (see below), whose sum is σ = 38259302400. Its totient is φ = 25406784000.
The previous prime is 31513212061. The next prime is 31513212113. The reversal of 31513212101 is 10121231513.
It is a cyclic number.
It is not a de Polignac number, because 31513212101 - 210 = 31513211077 is a prime.
It is a super-2 number, since 2×315132121012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31513212131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 240558806 + ... + 240558936.
It is an arithmetic number, because the mean of its divisors is an integer number (597801600).
Almost surely, 231513212101 is an apocalyptic number.
It is an amenable number.
31513212101 is a deficient number, since it is larger than the sum of its proper divisors (6746090299).
31513212101 is a wasteful number, since it uses less digits than its factorization.
31513212101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 450.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 31513212101 its reverse (10121231513), we get a palindrome (41634443614).
The spelling of 31513212101 in words is "thirty-one billion, five hundred thirteen million, two hundred twelve thousand, one hundred one".
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