Base | Representation |
---|---|
bin | 1001001010111111101… |
… | …11111100100011011001 |
3 | 1010010102201121022112211 |
4 | 10211133313330203121 |
5 | 20130402111122243 |
6 | 400435051435121 |
7 | 31524330162142 |
oct | 4453767744331 |
9 | 1103381538484 |
10 | 315141114073 |
11 | 111717a41415 |
12 | 510b0155aa1 |
13 | 239439850c6 |
14 | 11377dbaac9 |
15 | 82e6a99d9d |
hex | 495fdfc8d9 |
315141114073 has 2 divisors, whose sum is σ = 315141114074. Its totient is φ = 315141114072.
The previous prime is 315141114061. The next prime is 315141114077. The reversal of 315141114073 is 370411141513.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 315139645129 + 1468944 = 561373^2 + 1212^2 .
It is a cyclic number.
It is not a de Polignac number, because 315141114073 - 29 = 315141113561 is a prime.
It is not a weakly prime, because it can be changed into another prime (315141114077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157570557036 + 157570557037.
It is an arithmetic number, because the mean of its divisors is an integer number (157570557037).
Almost surely, 2315141114073 is an apocalyptic number.
It is an amenable number.
315141114073 is a deficient number, since it is larger than the sum of its proper divisors (1).
315141114073 is an equidigital number, since it uses as much as digits as its factorization.
315141114073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 315141114073 its reverse (370411141513), we get a palindrome (685552255586).
The spelling of 315141114073 in words is "three hundred fifteen billion, one hundred forty-one million, one hundred fourteen thousand, seventy-three".
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