Base | Representation |
---|---|
bin | 100011110100111101100011… |
… | …1101010001100001110010011 |
3 | 1112022211022022100102001212211 |
4 | 1013221323013222030032103 |
5 | 312301242342201242203 |
6 | 3034130210450132551 |
7 | 123244164324620056 |
oct | 10751730752141623 |
9 | 1468738270361784 |
10 | 315142280102803 |
11 | 914610aa41511a |
12 | 2b418827b81157 |
13 | 106aca356b302a |
14 | 57b6d796a8a9d |
15 | 2667891e85c6d |
hex | 11e9ec7a8c393 |
315142280102803 has 2 divisors, whose sum is σ = 315142280102804. Its totient is φ = 315142280102802.
The previous prime is 315142280102801. The next prime is 315142280102911. The reversal of 315142280102803 is 308201082241513.
It is a weak prime.
It is an emirp because it is prime and its reverse (308201082241513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 315142280102803 - 21 = 315142280102801 is a prime.
Together with 315142280102801, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (315142280102801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157571140051401 + 157571140051402.
It is an arithmetic number, because the mean of its divisors is an integer number (157571140051402).
Almost surely, 2315142280102803 is an apocalyptic number.
315142280102803 is a deficient number, since it is larger than the sum of its proper divisors (1).
315142280102803 is an equidigital number, since it uses as much as digits as its factorization.
315142280102803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 92160, while the sum is 40.
The spelling of 315142280102803 in words is "three hundred fifteen trillion, one hundred forty-two billion, two hundred eighty million, one hundred two thousand, eight hundred three".
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