Base | Representation |
---|---|
bin | 1011101111010111… |
… | …0011010010110001 |
3 | 22010121222220020121 |
4 | 2323311303102301 |
5 | 22423232134441 |
6 | 1240414210241 |
7 | 141044552551 |
oct | 27365632261 |
9 | 8117886217 |
10 | 3151443121 |
11 | 13779a8952 |
12 | 73b4b3981 |
13 | 3b2b9a258 |
14 | 21c789161 |
15 | 136a0add1 |
hex | bbd734b1 |
3151443121 has 2 divisors, whose sum is σ = 3151443122. Its totient is φ = 3151443120.
The previous prime is 3151443091. The next prime is 3151443149. The reversal of 3151443121 is 1213441513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2445797025 + 705646096 = 49455^2 + 26564^2 .
It is an emirp because it is prime and its reverse (1213441513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3151443121 - 25 = 3151443089 is a prime.
It is not a weakly prime, because it can be changed into another prime (3151443161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575721560 + 1575721561.
It is an arithmetic number, because the mean of its divisors is an integer number (1575721561).
Almost surely, 23151443121 is an apocalyptic number.
It is an amenable number.
3151443121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3151443121 is an equidigital number, since it uses as much as digits as its factorization.
3151443121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 25.
The square root of 3151443121 is about 56137.7156731551. The cubic root of 3151443121 is about 1466.1210336478.
Adding to 3151443121 its reverse (1213441513), we get a palindrome (4364884634).
The spelling of 3151443121 in words is "three billion, one hundred fifty-one million, four hundred forty-three thousand, one hundred twenty-one".
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