Base | Representation |
---|---|
bin | 1110010101001100010110… |
… | …10100110101000100111001 |
3 | 11010120202110120020112001102 |
4 | 13022212023110311010321 |
5 | 13112313210202402212 |
6 | 151005322303101145 |
7 | 6431563666533644 |
oct | 712461324650471 |
9 | 133522416215042 |
10 | 31514512544057 |
11 | a050258827604 |
12 | 364b8825a17b5 |
13 | 1477a623bc31a |
14 | 7ad44c1cca5b |
15 | 399b7129b5c2 |
hex | 1ca98b535139 |
31514512544057 has 2 divisors, whose sum is σ = 31514512544058. Its totient is φ = 31514512544056.
The previous prime is 31514512544051. The next prime is 31514512544083. The reversal of 31514512544057 is 75044521541513.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16891146493456 + 14623366050601 = 4109884^2 + 3824051^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31514512544057 is a prime.
It is not a weakly prime, because it can be changed into another prime (31514512544051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15757256272028 + 15757256272029.
It is an arithmetic number, because the mean of its divisors is an integer number (15757256272029).
Almost surely, 231514512544057 is an apocalyptic number.
It is an amenable number.
31514512544057 is a deficient number, since it is larger than the sum of its proper divisors (1).
31514512544057 is an equidigital number, since it uses as much as digits as its factorization.
31514512544057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1680000, while the sum is 47.
The spelling of 31514512544057 in words is "thirty-one trillion, five hundred fourteen billion, five hundred twelve million, five hundred forty-four thousand, fifty-seven".
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