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315145412041 is a prime number
BaseRepresentation
bin1001001011000000010…
…00010101110111001001
31010010110000200200020211
410211200020111313021
520130404211141131
6400435323521121
731524411542515
oct4454010256711
91103400620224
10315145412041
1111171a407559
12510b16891a1
132394482b495
14113787b9145
1582e71485b1
hex4960215dc9

315145412041 has 2 divisors, whose sum is σ = 315145412042. Its totient is φ = 315145412040.

The previous prime is 315145412039. The next prime is 315145412063. The reversal of 315145412041 is 140214541513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 271332642816 + 43812769225 = 520896^2 + 209315^2 .

It is a cyclic number.

It is not a de Polignac number, because 315145412041 - 21 = 315145412039 is a prime.

Together with 315145412039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 315145411994 and 315145412012.

It is not a weakly prime, because it can be changed into another prime (315145412011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157572706020 + 157572706021.

It is an arithmetic number, because the mean of its divisors is an integer number (157572706021).

Almost surely, 2315145412041 is an apocalyptic number.

It is an amenable number.

315145412041 is a deficient number, since it is larger than the sum of its proper divisors (1).

315145412041 is an equidigital number, since it uses as much as digits as its factorization.

315145412041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 315145412041 its reverse (140214541513), we get a palindrome (455359953554).

The spelling of 315145412041 in words is "three hundred fifteen billion, one hundred forty-five million, four hundred twelve thousand, forty-one".