Base | Representation |
---|---|
bin | 1001001011000001010… |
… | …11011001010001011011 |
3 | 1010010110122222112012112 |
4 | 10211200223121101123 |
5 | 20130414034213201 |
6 | 400440252502535 |
7 | 31524552623603 |
oct | 4454053312133 |
9 | 1103418875175 |
10 | 315154601051 |
11 | 111724613384 |
12 | 510b477aa4b |
13 | 239466c7b74 |
14 | 11379acbc03 |
15 | 82e7d610bb |
hex | 4960ad945b |
315154601051 has 2 divisors, whose sum is σ = 315154601052. Its totient is φ = 315154601050.
The previous prime is 315154601033. The next prime is 315154601071. The reversal of 315154601051 is 150106451513.
It is a weak prime.
It is an emirp because it is prime and its reverse (150106451513) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-315154601051 is a prime.
It is a super-2 number, since 2×3151546010512 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 315154600999 and 315154601017.
It is not a weakly prime, because it can be changed into another prime (315154601071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157577300525 + 157577300526.
It is an arithmetic number, because the mean of its divisors is an integer number (157577300526).
Almost surely, 2315154601051 is an apocalyptic number.
315154601051 is a deficient number, since it is larger than the sum of its proper divisors (1).
315154601051 is an equidigital number, since it uses as much as digits as its factorization.
315154601051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 32.
The spelling of 315154601051 in words is "three hundred fifteen billion, one hundred fifty-four million, six hundred one thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •