Base | Representation |
---|---|
bin | 1110010101010111010110… |
… | …11111101000100101000011 |
3 | 11010121022201022221222012021 |
4 | 13022223223133220211003 |
5 | 13112412310231101413 |
6 | 151012140444542311 |
7 | 6432163262315104 |
oct | 712535337504503 |
9 | 133538638858167 |
10 | 31520420956483 |
11 | a05280a992288 |
12 | 3650a51251997 |
13 | 14784944cb654 |
14 | 7ad84cb9a3ab |
15 | 399db9d4218d |
hex | 1caaeb7e8943 |
31520420956483 has 2 divisors, whose sum is σ = 31520420956484. Its totient is φ = 31520420956482.
The previous prime is 31520420956481. The next prime is 31520420956487. The reversal of 31520420956483 is 38465902402513.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31520420956483 - 21 = 31520420956481 is a prime.
Together with 31520420956481, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 31520420956483.
It is not a weakly prime, because it can be changed into another prime (31520420956481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15760210478241 + 15760210478242.
It is an arithmetic number, because the mean of its divisors is an integer number (15760210478242).
Almost surely, 231520420956483 is an apocalyptic number.
31520420956483 is a deficient number, since it is larger than the sum of its proper divisors (1).
31520420956483 is an equidigital number, since it uses as much as digits as its factorization.
31520420956483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6220800, while the sum is 52.
The spelling of 31520420956483 in words is "thirty-one trillion, five hundred twenty billion, four hundred twenty million, nine hundred fifty-six thousand, four hundred eighty-three".
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