Base | Representation |
---|---|
bin | 101101110111110110010… |
… | …001100111111111001101 |
3 | 102011100202012012120012021 |
4 | 231313312101213333031 |
5 | 403121444231441331 |
6 | 10412055531210141 |
7 | 443514665026306 |
oct | 55676621477715 |
9 | 12140665176167 |
10 | 3152342843341 |
11 | 10059a039879a |
12 | 42ab412a6951 |
13 | 19b3595a52a3 |
14 | ac8078a97ad |
15 | 56eedd59211 |
hex | 2ddf6467fcd |
3152342843341 has 2 divisors, whose sum is σ = 3152342843342. Its totient is φ = 3152342843340.
The previous prime is 3152342843329. The next prime is 3152342843347. The reversal of 3152342843341 is 1433482432513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2259072126441 + 893270716900 = 1503021^2 + 945130^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3152342843341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3152342843347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1576171421670 + 1576171421671.
It is an arithmetic number, because the mean of its divisors is an integer number (1576171421671).
Almost surely, 23152342843341 is an apocalyptic number.
It is an amenable number.
3152342843341 is a deficient number, since it is larger than the sum of its proper divisors (1).
3152342843341 is an equidigital number, since it uses as much as digits as its factorization.
3152342843341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 829440, while the sum is 43.
The spelling of 3152342843341 in words is "three trillion, one hundred fifty-two billion, three hundred forty-two million, eight hundred forty-three thousand, three hundred forty-one".
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