Base | Representation |
---|---|
bin | 1001001011001011110… |
… | …01010101001010111111 |
3 | 1010010200202200222112211 |
4 | 10211211321111022333 |
5 | 20131103441442401 |
6 | 400453101041251 |
7 | 31526664660325 |
oct | 4454571251277 |
9 | 1103622628484 |
10 | 315242140351 |
11 | 111769a73a06 |
12 | 51119b56227 |
13 | 2395b897a78 |
14 | 11387597d15 |
15 | 83008a3951 |
hex | 4965e552bf |
315242140351 has 2 divisors, whose sum is σ = 315242140352. Its totient is φ = 315242140350.
The previous prime is 315242140333. The next prime is 315242140363. The reversal of 315242140351 is 153041242513.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 315242140351 - 211 = 315242138303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315242140751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157621070175 + 157621070176.
It is an arithmetic number, because the mean of its divisors is an integer number (157621070176).
Almost surely, 2315242140351 is an apocalyptic number.
315242140351 is a deficient number, since it is larger than the sum of its proper divisors (1).
315242140351 is an equidigital number, since it uses as much as digits as its factorization.
315242140351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 315242140351 its reverse (153041242513), we get a palindrome (468283382864).
The spelling of 315242140351 in words is "three hundred fifteen billion, two hundred forty-two million, one hundred forty thousand, three hundred fifty-one".
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