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315295876684807 is a prime number
BaseRepresentation
bin100011110110000101000101…
…0101110101001110000000111
31112100100222202202110212202021
41013230022022232221300013
5312311301423412403212
63034324532014024011
7123261242515206124
oct10754121256516007
91470328682425667
10315295876684807
1191510259707597
122b4425531a8007
13106c1373116905
1457c058a99974b
15266b88169e307
hex11ec28aba9c07

315295876684807 has 2 divisors, whose sum is σ = 315295876684808. Its totient is φ = 315295876684806.

The previous prime is 315295876684729. The next prime is 315295876684819. The reversal of 315295876684807 is 708486678592513.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-315295876684807 is a prime.

It is a super-2 number, since 2×3152958766848072 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (315295876684307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157647938342403 + 157647938342404.

It is an arithmetic number, because the mean of its divisors is an integer number (157647938342404).

It is a 1-persistent number, because it is pandigital, but 2⋅315295876684807 = 630591753369614 is not.

Almost surely, 2315295876684807 is an apocalyptic number.

315295876684807 is a deficient number, since it is larger than the sum of its proper divisors (1).

315295876684807 is an equidigital number, since it uses as much as digits as its factorization.

315295876684807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4877107200, while the sum is 79.

The spelling of 315295876684807 in words is "three hundred fifteen trillion, two hundred ninety-five billion, eight hundred seventy-six million, six hundred eighty-four thousand, eight hundred seven".