Base | Representation |
---|---|
bin | 101101111000100011101… |
… | …101110101111010101011 |
3 | 102011102201022202001201002 |
4 | 231320203231311322223 |
5 | 403130024413341042 |
6 | 10412303323345215 |
7 | 443542613053526 |
oct | 55704355657253 |
9 | 12142638661632 |
10 | 3153105215147 |
11 | 1006251768a38 |
12 | 42b11468220b |
13 | 19b44b512074 |
14 | ac87ac3bbbd |
15 | 57045c4c132 |
hex | 2de23b75eab |
3153105215147 has 2 divisors, whose sum is σ = 3153105215148. Its totient is φ = 3153105215146.
The previous prime is 3153105215077. The next prime is 3153105215177. The reversal of 3153105215147 is 7415125013513.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3153105215147 - 28 = 3153105214891 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3153105215147.
It is not a weakly prime, because it can be changed into another prime (3153105215177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1576552607573 + 1576552607574.
It is an arithmetic number, because the mean of its divisors is an integer number (1576552607574).
Almost surely, 23153105215147 is an apocalyptic number.
3153105215147 is a deficient number, since it is larger than the sum of its proper divisors (1).
3153105215147 is an equidigital number, since it uses as much as digits as its factorization.
3153105215147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 38.
The spelling of 3153105215147 in words is "three trillion, one hundred fifty-three billion, one hundred five million, two hundred fifteen thousand, one hundred forty-seven".
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