3153130013213 has 2 divisors, whose sum is σ = 3153130013214. Its totient is φ = 3153130013212.

The previous prime is 3153130013197. The next prime is 3153130013221. The reversal of 3153130013213 is 3123100313513.

3153130013213 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1648930787449 + 1504199225764 = 1284107^2 + 1226458^2 .

It is an emirp because it is prime and its reverse (3123100313513) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3153130013213 - 2⁴ = 3153130013197 is a prime.

It is a super-2 number, since 2×3153130013213² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3153130013113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1576565006606 + 1576565006607.

It is an arithmetic number, because the mean of its divisors is an integer number (1576565006607).

Almost surely, 2^{3153130013213} is an apocalyptic number.

It is an amenable number.

3153130013213 is a deficient number, since it is larger than the sum of its proper divisors (1).

3153130013213 is an equidigital number, since it uses as much as digits as its factorization.

3153130013213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2430, while the sum is 26.

Adding to 3153130013213 its reverse (3123100313513), we get a palindrome (6276230326726).

It can be divided in two parts, 31531300 and 13213, that added together give a palindrome (31544513).

The spelling of 3153130013213 in words is "three trillion, one hundred fifty-three billion, one hundred thirty million, thirteen thousand, two hundred thirteen".