Base | Representation |
---|---|
bin | 101101111001011001110… |
… | …010100100100011110000 |
3 | 102011112001112211001212222 |
4 | 231321121302210203300 |
5 | 403133404140040212 |
6 | 10412533332140212 |
7 | 443604240156542 |
oct | 55713162444360 |
9 | 12145045731788 |
10 | 3154012424432 |
11 | 1006677874781 |
12 | 42b328467668 |
13 | 19b564460cac |
14 | ac925513692 |
15 | 5709a6eec72 |
hex | 2de59ca48f0 |
3154012424432 has 40 divisors (see below), whose sum is σ = 6411435153792. Its totient is φ = 1501116422400.
The previous prime is 3154012424419. The next prime is 3154012424467. The reversal of 3154012424432 is 2344242104513.
3154012424432 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 3154012424392 and 3154012424401.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52091843 + ... + 52152354.
Almost surely, 23154012424432 is an apocalyptic number.
It is an amenable number.
3154012424432 is an abundant number, since it is smaller than the sum of its proper divisors (3257422729360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3154012424432 is a wasteful number, since it uses less digits than its factorization.
3154012424432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104244297 (or 104244291 counting only the distinct ones).
The product of its (nonzero) digits is 92160, while the sum is 35.
Adding to 3154012424432 its reverse (2344242104513), we get a palindrome (5498254528945).
The spelling of 3154012424432 in words is "three trillion, one hundred fifty-four billion, twelve million, four hundred twenty-four thousand, four hundred thirty-two".
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