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31540215313 is a prime number
BaseRepresentation
bin11101010111111100…
…010111111000010001
310000102002110221120201
4131113330113320101
51004043243342223
622253412135201
72164411256335
oct352774277021
9100362427521
1031540215313
11124156a1652
126142907501
132c884c7bc9
141752c197c5
15c48e68ead
hex757f17e11

31540215313 has 2 divisors, whose sum is σ = 31540215314. Its totient is φ = 31540215312.

The previous prime is 31540215283. The next prime is 31540215373. The reversal of 31540215313 is 31351204513.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28273749904 + 3266465409 = 168148^2 + 57153^2 .

It is an emirp because it is prime and its reverse (31351204513) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31540215313 - 229 = 31003344401 is a prime.

It is not a weakly prime, because it can be changed into another prime (31540215373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15770107656 + 15770107657.

It is an arithmetic number, because the mean of its divisors is an integer number (15770107657).

Almost surely, 231540215313 is an apocalyptic number.

It is an amenable number.

31540215313 is a deficient number, since it is larger than the sum of its proper divisors (1).

31540215313 is an equidigital number, since it uses as much as digits as its factorization.

31540215313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 31540215313 its reverse (31351204513), we get a palindrome (62891419826).

The spelling of 31540215313 in words is "thirty-one billion, five hundred forty million, two hundred fifteen thousand, three hundred thirteen".