Base | Representation |
---|---|
bin | 11101010111111100… |
… | …101101001001110101 |
3 | 10000102002122101010010 |
4 | 131113330231021311 |
5 | 1004043304134303 |
6 | 22253414050433 |
7 | 2164412101362 |
oct | 352774551165 |
9 | 100362571103 |
10 | 31540302453 |
11 | 12415751070 |
12 | 6142949a19 |
13 | 2c8852877a |
14 | 1752c3d469 |
15 | c48e84c03 |
hex | 757f2d275 |
31540302453 has 64 divisors (see below), whose sum is σ = 49026124800. Its totient is φ = 17824834560.
The previous prime is 31540302421. The next prime is 31540302551. The reversal of 31540302453 is 35420304513.
It is not a de Polignac number, because 31540302453 - 25 = 31540302421 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 31540302453.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31540302853) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 44485263 + ... + 44485971.
It is an arithmetic number, because the mean of its divisors is an integer number (766033200).
Almost surely, 231540302453 is an apocalyptic number.
31540302453 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31540302453 is a deficient number, since it is larger than the sum of its proper divisors (17485822347).
31540302453 is a wasteful number, since it uses less digits than its factorization.
31540302453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1362.
The product of its (nonzero) digits is 21600, while the sum is 30.
Adding to 31540302453 its reverse (35420304513), we get a palindrome (66960606966).
The spelling of 31540302453 in words is "thirty-one billion, five hundred forty million, three hundred two thousand, four hundred fifty-three".
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