Base | Representation |
---|---|
bin | 1110010101111100011111… |
… | …00011100111101101101001 |
3 | 11010200020011110020200000002 |
4 | 13022332033203213231221 |
5 | 13113224120423142441 |
6 | 151025234400552345 |
7 | 6433500233610212 |
oct | 712761743475551 |
9 | 133606143220002 |
10 | 31540353334121 |
11 | a060209224655 |
12 | 36548946226b5 |
13 | 147a31cb8aa48 |
14 | 7b07c00bc409 |
15 | 39a684ba1b9b |
hex | 1caf8f8e7b69 |
31540353334121 has 2 divisors, whose sum is σ = 31540353334122. Its totient is φ = 31540353334120.
The previous prime is 31540353334081. The next prime is 31540353334199. The reversal of 31540353334121 is 12143335304513.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19440947637721 + 12099405696400 = 4409189^2 + 3478420^2 .
It is a cyclic number.
It is not a de Polignac number, because 31540353334121 - 218 = 31540353071977 is a prime.
It is not a weakly prime, because it can be changed into another prime (31540353354121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15770176667060 + 15770176667061.
It is an arithmetic number, because the mean of its divisors is an integer number (15770176667061).
Almost surely, 231540353334121 is an apocalyptic number.
It is an amenable number.
31540353334121 is a deficient number, since it is larger than the sum of its proper divisors (1).
31540353334121 is an equidigital number, since it uses as much as digits as its factorization.
31540353334121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 38.
Adding to 31540353334121 its reverse (12143335304513), we get a palindrome (43683688638634).
The spelling of 31540353334121 in words is "thirty-one trillion, five hundred forty billion, three hundred fifty-three million, three hundred thirty-four thousand, one hundred twenty-one".
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