31540452131 has 2 divisors, whose sum is σ = 31540452132. Its totient is φ = 31540452130.

The previous prime is 31540452127. The next prime is 31540452133. The reversal of 31540452131 is 13125404513.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31540452131 - 2² = 31540452127 is a prime.

It is a super-2 number, since 2×31540452131² (a number of 22 digits) contains 22 as substring.

Together with 31540452133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 31540452094 and 31540452103.

It is not a weakly prime, because it can be changed into another prime (31540452133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15770226065 + 15770226066.

It is an arithmetic number, because the mean of its divisors is an integer number (15770226066).

Almost surely, 2^31540452131 is an apocalyptic number.

31540452131 is a deficient number, since it is larger than the sum of its proper divisors (1).

31540452131 is an equidigital number, since it uses as much as digits as its factorization.

31540452131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 31540452131 its reverse (13125404513), we get a palindrome (44665856644).

The spelling of 31540452131 in words is "thirty-one billion, five hundred forty million, four hundred fifty-two thousand, one hundred thirty-one".