Base | Representation |
---|---|
bin | 1110010110000000010111… |
… | …00101001010011001101110 |
3 | 11010200102112110121012012110 |
4 | 13023000023211022121232 |
5 | 13113242401113110014 |
6 | 151030221051144450 |
7 | 6433602631131300 |
oct | 713001345123156 |
9 | 133612473535173 |
10 | 31542434113134 |
11 | a06108682472a |
12 | 3655175445126 |
13 | 147a591ca8c29 |
14 | 7b093a5a3970 |
15 | 39a7576bdd59 |
hex | 1cb00b94a66e |
31542434113134 has 48 divisors (see below), whose sum is σ = 73397710175616. Its totient is φ = 9010494183600.
The previous prime is 31542434113111. The next prime is 31542434113181. The reversal of 31542434113134 is 43131143424513.
It is a happy number.
It is a super-2 number, since 2×315424341131342 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31542434113092 and 31542434113101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8072602 + ... + 11324829.
It is an arithmetic number, because the mean of its divisors is an integer number (1529118961992).
Almost surely, 231542434113134 is an apocalyptic number.
31542434113134 is an abundant number, since it is smaller than the sum of its proper divisors (41855276062482).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31542434113134 is a wasteful number, since it uses less digits than its factorization.
31542434113134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19402981 (or 19402974 counting only the distinct ones).
The product of its digits is 207360, while the sum is 39.
Adding to 31542434113134 its reverse (43131143424513), we get a palindrome (74673577537647).
The spelling of 31542434113134 in words is "thirty-one trillion, five hundred forty-two billion, four hundred thirty-four million, one hundred thirteen thousand, one hundred thirty-four".
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