Search a number
-
+
315440102544131 is a prime number
BaseRepresentation
bin100011110111001000001111…
…1010000101001001100000011
31112100212210001002212122200202
41013232100133100221030003
5312321132312222403011
63034515103234435415
7123304536541611035
oct10756203720511403
91470783032778622
10315440102544131
119156643a41a354
122b4664a4132b6b
1310701b49339986
1457c754d531c55
1526704c33ac23b
hex11ee41f429303

315440102544131 has 2 divisors, whose sum is σ = 315440102544132. Its totient is φ = 315440102544130.

The previous prime is 315440102544113. The next prime is 315440102544139. The reversal of 315440102544131 is 131445201044513.

Together with previous prime (315440102544113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 315440102544131 - 226 = 315440035435267 is a prime.

It is a super-2 number, since 2×3154401025441312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (315440102544139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157720051272065 + 157720051272066.

It is an arithmetic number, because the mean of its divisors is an integer number (157720051272066).

Almost surely, 2315440102544131 is an apocalyptic number.

315440102544131 is a deficient number, since it is larger than the sum of its proper divisors (1).

315440102544131 is an equidigital number, since it uses as much as digits as its factorization.

315440102544131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 315440102544131 its reverse (131445201044513), we get a palindrome (446885303588644).

The spelling of 315440102544131 in words is "three hundred fifteen trillion, four hundred forty billion, one hundred two million, five hundred forty-four thousand, one hundred thirty-one".