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31545083860453 is a prime number
BaseRepresentation
bin1110010110000101010011…
…00001001001010111100101
311010200200101010120022012001
413023002221201021113211
513113313312432013303
6151031340024325301
76434025404455162
oct713025141112745
9133620333508161
1031545083860453
11a062216508049
123655794913831
13147a8c4c49257
147b0b0c475069
1539a86012931d
hex1cb0a98495e5

31545083860453 has 2 divisors, whose sum is σ = 31545083860454. Its totient is φ = 31545083860452.

The previous prime is 31545083860387. The next prime is 31545083860481. The reversal of 31545083860453 is 35406838054513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29374904099044 + 2170179761409 = 5419862^2 + 1473153^2 .

It is a cyclic number.

It is not a de Polignac number, because 31545083860453 - 29 = 31545083859941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31545083860394 and 31545083860403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31545083863453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15772541930226 + 15772541930227.

It is an arithmetic number, because the mean of its divisors is an integer number (15772541930227).

Almost surely, 231545083860453 is an apocalyptic number.

It is an amenable number.

31545083860453 is a deficient number, since it is larger than the sum of its proper divisors (1).

31545083860453 is an equidigital number, since it uses as much as digits as its factorization.

31545083860453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736000, while the sum is 55.

The spelling of 31545083860453 in words is "thirty-one trillion, five hundred forty-five billion, eighty-three million, eight hundred sixty thousand, four hundred fifty-three".