Base | Representation |
---|---|
bin | 101101111010110100011… |
… | …000111011101011000101 |
3 | 102011122222110222100120021 |
4 | 231322310120323223011 |
5 | 403200012300230041 |
6 | 10413344231135141 |
7 | 443660015045656 |
oct | 55726430735305 |
9 | 12148873870507 |
10 | 3155532430021 |
11 | 1007287879444 |
12 | 42b6915144b1 |
13 | 19b74733909a |
14 | aca2b34352d |
15 | 57138d9bcd1 |
hex | 2deb463bac5 |
3155532430021 has 4 divisors (see below), whose sum is σ = 3156303769344. Its totient is φ = 3154761090700.
The previous prime is 3155532429899. The next prime is 3155532430073. The reversal of 3155532430021 is 1200342355513.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3155532430021 - 27 = 3155532429893 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3155532439021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385663525 + ... + 385671706.
It is an arithmetic number, because the mean of its divisors is an integer number (789075942336).
Almost surely, 23155532430021 is an apocalyptic number.
It is an amenable number.
3155532430021 is a deficient number, since it is larger than the sum of its proper divisors (771339323).
3155532430021 is an equidigital number, since it uses as much as digits as its factorization.
3155532430021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 771339322.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 3155532430021 its reverse (1200342355513), we get a palindrome (4355874785534).
The spelling of 3155532430021 in words is "three trillion, one hundred fifty-five billion, five hundred thirty-two million, four hundred thirty thousand, twenty-one".
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