Base | Representation |
---|---|
bin | 101101111010111001011… |
… | …001110010110100111011 |
3 | 102011200012100020200112011 |
4 | 231322321121302310323 |
5 | 403200200313321021 |
6 | 10413400434030351 |
7 | 443662056016303 |
oct | 55727131626473 |
9 | 12150170220464 |
10 | 3155616542011 |
11 | 10073202a8a8a |
12 | 42b6b57183b7 |
13 | 19b75b8a8cab |
14 | aca3859a603 |
15 | 57141463de1 |
hex | 2deb9672d3b |
3155616542011 has 2 divisors, whose sum is σ = 3155616542012. Its totient is φ = 3155616542010.
The previous prime is 3155616542009. The next prime is 3155616542017. The reversal of 3155616542011 is 1102456165513.
It is a weak prime.
It is an emirp because it is prime and its reverse (1102456165513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3155616542011 - 21 = 3155616542009 is a prime.
It is a super-2 number, since 2×31556165420112 (a number of 26 digits) contains 22 as substring.
Together with 3155616542009, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3155616542017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1577808271005 + 1577808271006.
It is an arithmetic number, because the mean of its divisors is an integer number (1577808271006).
Almost surely, 23155616542011 is an apocalyptic number.
3155616542011 is a deficient number, since it is larger than the sum of its proper divisors (1).
3155616542011 is an equidigital number, since it uses as much as digits as its factorization.
3155616542011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 40.
The spelling of 3155616542011 in words is "three trillion, one hundred fifty-five billion, six hundred sixteen million, five hundred forty-two thousand, eleven".
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