315659691253 has 2 divisors, whose sum is σ = 315659691254. Its totient is φ = 315659691252.

The previous prime is 315659691209. The next prime is 315659691283. The reversal of 315659691253 is 352196956513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 271422244324 + 44237446929 = 520982^2 + 210327^2 .

It is a cyclic number.

It is not a de Polignac number, because 315659691253 - 2³³ = 307069756661 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 315659691194 and 315659691203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (315659691283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157829845626 + 157829845627.

It is an arithmetic number, because the mean of its divisors is an integer number (157829845627).

Almost surely, 2^315659691253 is an apocalyptic number.

It is an amenable number.

315659691253 is a deficient number, since it is larger than the sum of its proper divisors (1).

315659691253 is an equidigital number, since it uses as much as digits as its factorization.

315659691253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6561000, while the sum is 55.

The spelling of 315659691253 in words is "three hundred fifteen billion, six hundred fifty-nine million, six hundred ninety-one thousand, two hundred fifty-three".