Base | Representation |
---|---|
bin | 101101111101110011100… |
… | …101110001001010111101 |
3 | 102011222021001001010220022 |
4 | 231331303211301022331 |
5 | 403223100000240013 |
6 | 10415034421501525 |
7 | 444132346026536 |
oct | 55756345611275 |
9 | 12158231033808 |
10 | 3158740243133 |
11 | 1008683578962 |
12 | 4302278718a5 |
13 | 19bb38ab1c57 |
14 | acc533a368d |
15 | 572757e0008 |
hex | 2df739712bd |
3158740243133 has 2 divisors, whose sum is σ = 3158740243134. Its totient is φ = 3158740243132.
The previous prime is 3158740243117. The next prime is 3158740243163. The reversal of 3158740243133 is 3313420478513.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1971769214809 + 1186971028324 = 1404197^2 + 1089482^2 .
It is an emirp because it is prime and its reverse (3313420478513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3158740243133 - 24 = 3158740243117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3158740243163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1579370121566 + 1579370121567.
It is an arithmetic number, because the mean of its divisors is an integer number (1579370121567).
Almost surely, 23158740243133 is an apocalyptic number.
It is an amenable number.
3158740243133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3158740243133 is an equidigital number, since it uses as much as digits as its factorization.
3158740243133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 44.
The spelling of 3158740243133 in words is "three trillion, one hundred fifty-eight billion, seven hundred forty million, two hundred forty-three thousand, one hundred thirty-three".
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