Base | Representation |
---|---|
bin | 101110000000000110101… |
… | …101100001001011110101 |
3 | 102012012122001112212211212 |
4 | 232000012231201023311 |
5 | 403243123340304212 |
6 | 10420123353411205 |
7 | 444250460054315 |
oct | 56000655411365 |
9 | 12165561485755 |
10 | 3161208525557 |
11 | 100972a888a95 |
12 | 4307b6409b05 |
13 | 19c1402876b4 |
14 | ad009119445 |
15 | 5736c352e22 |
hex | 2e006b612f5 |
3161208525557 has 2 divisors, whose sum is σ = 3161208525558. Its totient is φ = 3161208525556.
The previous prime is 3161208525529. The next prime is 3161208525571. The reversal of 3161208525557 is 7555258021613.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3115397972401 + 45810553156 = 1765049^2 + 214034^2 .
It is a cyclic number.
It is not a de Polignac number, because 3161208525557 - 210 = 3161208524533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3161208525157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1580604262778 + 1580604262779.
It is an arithmetic number, because the mean of its divisors is an integer number (1580604262779).
Almost surely, 23161208525557 is an apocalyptic number.
It is an amenable number.
3161208525557 is a deficient number, since it is larger than the sum of its proper divisors (1).
3161208525557 is an equidigital number, since it uses as much as digits as its factorization.
3161208525557 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520000, while the sum is 50.
The spelling of 3161208525557 in words is "three trillion, one hundred sixty-one billion, two hundred eight million, five hundred twenty-five thousand, five hundred fifty-seven".
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