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316166532455513 is a prime number
BaseRepresentation
bin100011111100011010100000…
…1110110110101110001011001
31112110110020002020220122220102
41013320311001312311301121
5312420033024302034023
63040232522212505145
7123411164261150555
oct10770650166656131
91473406066818812
10316166532455513
1191816523143613
122b56323801b1b5
13107554b733241c
145810782a7a865
15268433c939628
hex11f8d41db5c59

316166532455513 has 2 divisors, whose sum is σ = 316166532455514. Its totient is φ = 316166532455512.

The previous prime is 316166532455489. The next prime is 316166532455537. The reversal of 316166532455513 is 315554235661613.

It is a balanced prime because it is at equal distance from previous prime (316166532455489) and next prime (316166532455537).

It can be written as a sum of positive squares in only one way, i.e., 235777161271369 + 80389371184144 = 15355037^2 + 8966012^2 .

It is a cyclic number.

It is not a de Polignac number, because 316166532455513 - 212 = 316166532451417 is a prime.

It is a super-2 number, since 2×3161665324555132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (316166532455413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158083266227756 + 158083266227757.

It is an arithmetic number, because the mean of its divisors is an integer number (158083266227757).

Almost surely, 2316166532455513 is an apocalyptic number.

It is an amenable number.

316166532455513 is a deficient number, since it is larger than the sum of its proper divisors (1).

316166532455513 is an equidigital number, since it uses as much as digits as its factorization.

316166532455513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 29160000, while the sum is 56.

The spelling of 316166532455513 in words is "three hundred sixteen trillion, one hundred sixty-six billion, five hundred thirty-two million, four hundred fifty-five thousand, five hundred thirteen".