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316256056542017 is a prime number
BaseRepresentation
bin100011111101000100001100…
…1111010001000001101000001
31112110202210011100021110102222
41013322020121322020031001
5312423014400433321032
63040342005432420425
7123420513621266324
oct10772103172101501
91473683140243388
10316256056542017
1191850493159869
122b578661547715
1310760a83683a87
145814c366927bb
15268682c109a12
hex11fa219e88341

316256056542017 has 2 divisors, whose sum is σ = 316256056542018. Its totient is φ = 316256056542016.

The previous prime is 316256056542011. The next prime is 316256056542053. The reversal of 316256056542017 is 710245650652613.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 307233728711056 + 9022327830961 = 17528084^2 + 3003719^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-316256056542017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 316256056542017.

It is not a weakly prime, because it can be changed into another prime (316256056542011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158128028271008 + 158128028271009.

It is an arithmetic number, because the mean of its divisors is an integer number (158128028271009).

Almost surely, 2316256056542017 is an apocalyptic number.

It is an amenable number.

316256056542017 is a deficient number, since it is larger than the sum of its proper divisors (1).

316256056542017 is an equidigital number, since it uses as much as digits as its factorization.

316256056542017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072000, while the sum is 53.

The spelling of 316256056542017 in words is "three hundred sixteen trillion, two hundred fifty-six billion, fifty-six million, five hundred forty-two thousand, seventeen".