Base | Representation |
---|---|
bin | 101110000001110111001… |
… | …100001011000001000101 |
3 | 102012101111120102200020112 |
4 | 232001313030023001011 |
5 | 403311004434000123 |
6 | 10421034524242405 |
7 | 444345313030445 |
oct | 56016714130105 |
9 | 12171446380215 |
10 | 3163095609413 |
11 | 100a509012023 |
12 | 4310423a0405 |
13 | 19c38121826c |
14 | ad1479c0125 |
15 | 5742cd5dd78 |
hex | 2e07730b045 |
3163095609413 has 2 divisors, whose sum is σ = 3163095609414. Its totient is φ = 3163095609412.
The previous prime is 3163095609379. The next prime is 3163095609481. The reversal of 3163095609413 is 3149065903613.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2150701441729 + 1012394167684 = 1466527^2 + 1006178^2 .
It is a cyclic number.
It is not a de Polignac number, because 3163095609413 - 226 = 3163028500549 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3163095602413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1581547804706 + 1581547804707.
It is an arithmetic number, because the mean of its divisors is an integer number (1581547804707).
Almost surely, 23163095609413 is an apocalyptic number.
It is an amenable number.
3163095609413 is a deficient number, since it is larger than the sum of its proper divisors (1).
3163095609413 is an equidigital number, since it uses as much as digits as its factorization.
3163095609413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1574640, while the sum is 50.
The spelling of 3163095609413 in words is "three trillion, one hundred sixty-three billion, ninety-five million, six hundred nine thousand, four hundred thirteen".
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