Base | Representation |
---|---|
bin | 100011111101011111011010… |
… | …1101011011001011111100111 |
3 | 1112110222101000200102102110211 |
4 | 1013322332311223121133213 |
5 | 312424444101123014343 |
6 | 3040424513255200251 |
7 | 123424653203611624 |
oct | 10772766553313747 |
9 | 1473871020372424 |
10 | 316314504501223 |
11 | 91873256541688 |
12 | 2b587a53676087 |
13 | 107664396ca717 |
14 | 58179bcd7734b |
15 | 26880ed48379d |
hex | 11fafb5ad97e7 |
316314504501223 has 2 divisors, whose sum is σ = 316314504501224. Its totient is φ = 316314504501222.
The previous prime is 316314504501089. The next prime is 316314504501251. The reversal of 316314504501223 is 322105405413613.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 316314504501223 - 29 = 316314504500711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (316314504501923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158157252250611 + 158157252250612.
It is an arithmetic number, because the mean of its divisors is an integer number (158157252250612).
Almost surely, 2316314504501223 is an apocalyptic number.
316314504501223 is a deficient number, since it is larger than the sum of its proper divisors (1).
316314504501223 is an equidigital number, since it uses as much as digits as its factorization.
316314504501223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 316314504501223 its reverse (322105405413613), we get a palindrome (638419909914836).
The spelling of 316314504501223 in words is "three hundred sixteen trillion, three hundred fourteen billion, five hundred four million, five hundred one thousand, two hundred twenty-three".
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