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316403315554159 is a prime number
BaseRepresentation
bin100011111110001000110001…
…1001110101011011101101111
31112111021212021002002100211201
41013330101203032223131233
5312432422442240213114
63040533402044230331
7123434246055243331
oct10774214316533557
91474255232070751
10316403315554159
11918a7990016199
122b5a10ba23b3a7
13107719210c8412
14581c005dc1451
15268a59a259874
hex11fc4633ab76f

316403315554159 has 2 divisors, whose sum is σ = 316403315554160. Its totient is φ = 316403315554158.

The previous prime is 316403315554127. The next prime is 316403315554163. The reversal of 316403315554159 is 951455513304613.

It is a strong prime.

It is an emirp because it is prime and its reverse (951455513304613) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 316403315554159 - 25 = 316403315554127 is a prime.

It is a super-2 number, since 2×3164033155541592 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (316403315584159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158201657777079 + 158201657777080.

It is an arithmetic number, because the mean of its divisors is an integer number (158201657777080).

Almost surely, 2316403315554159 is an apocalyptic number.

316403315554159 is a deficient number, since it is larger than the sum of its proper divisors (1).

316403315554159 is an equidigital number, since it uses as much as digits as its factorization.

316403315554159 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14580000, while the sum is 55.

The spelling of 316403315554159 in words is "three hundred sixteen trillion, four hundred three billion, three hundred fifteen million, five hundred fifty-four thousand, one hundred fifty-nine".