Base | Representation |
---|---|
bin | 100011111110010101101010… |
… | …1101010000111001110010011 |
3 | 1112111101111201210221200110221 |
4 | 1013330223111222013032103 |
5 | 312433401144304332042 |
6 | 3040554221424333511 |
7 | 123436246202035264 |
oct | 10774532552071623 |
9 | 1474344653850427 |
10 | 316431005152147 |
11 | 919086aa083a76 |
12 | 2b5a6547474297 |
13 | 10774414915822 |
14 | 581d4b165096b |
15 | 268b16b109d67 |
hex | 11fcad5a87393 |
316431005152147 has 2 divisors, whose sum is σ = 316431005152148. Its totient is φ = 316431005152146.
The previous prime is 316431005152079. The next prime is 316431005152181. The reversal of 316431005152147 is 741251500134613.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 316431005152147 - 243 = 307634912129939 is a prime.
It is not a weakly prime, because it can be changed into another prime (316431005162147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158215502576073 + 158215502576074.
It is an arithmetic number, because the mean of its divisors is an integer number (158215502576074).
Almost surely, 2316431005152147 is an apocalyptic number.
316431005152147 is a deficient number, since it is larger than the sum of its proper divisors (1).
316431005152147 is an equidigital number, since it uses as much as digits as its factorization.
316431005152147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 316431005152147 in words is "three hundred sixteen trillion, four hundred thirty-one billion, five million, one hundred fifty-two thousand, one hundred forty-seven".
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