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316850428457 is a prime number
BaseRepresentation
bin1001001110001011100…
…00011101101000101001
31010021211211222111001222
410213011300131220221
520142402202202312
6401320432151425
731614564130043
oct4470560355051
91107754874058
10316850428457
11112414896632
12514a8698575
1323b56b43134
141149b008a93
158396b8d672
hex49c5c1da29

316850428457 has 2 divisors, whose sum is σ = 316850428458. Its totient is φ = 316850428456.

The previous prime is 316850428439. The next prime is 316850428481. The reversal of 316850428457 is 754824058613.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 314299269376 + 2551159081 = 560624^2 + 50509^2 .

It is a cyclic number.

It is not a de Polignac number, because 316850428457 - 224 = 316833651241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 316850428399 and 316850428408.

It is not a weakly prime, because it can be changed into another prime (316855428457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158425214228 + 158425214229.

It is an arithmetic number, because the mean of its divisors is an integer number (158425214229).

Almost surely, 2316850428457 is an apocalyptic number.

It is an amenable number.

316850428457 is a deficient number, since it is larger than the sum of its proper divisors (1).

316850428457 is an equidigital number, since it uses as much as digits as its factorization.

316850428457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6451200, while the sum is 53.

The spelling of 316850428457 in words is "three hundred sixteen billion, eight hundred fifty million, four hundred twenty-eight thousand, four hundred fifty-seven".