Base | Representation |
---|---|
bin | 100100000010101001101001… |
… | …0111011100110000101100011 |
3 | 1112120111011111021210210112222 |
4 | 1020011103102323212011203 |
5 | 313023103431202441321 |
6 | 3042130354443341255 |
7 | 123530126644505606 |
oct | 11005232273460543 |
9 | 1476434437723488 |
10 | 317023664890211 |
11 | 92016a8804a094 |
12 | 2b681387b2182b |
13 | 107b8284913476 |
14 | 5840054ac433d |
15 | 269b7a684a3ab |
hex | 12054d2ee6163 |
317023664890211 has 2 divisors, whose sum is σ = 317023664890212. Its totient is φ = 317023664890210.
The previous prime is 317023664890157. The next prime is 317023664890241. The reversal of 317023664890211 is 112098466320713.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-317023664890211 is a prime.
It is not a weakly prime, because it can be changed into another prime (317023664890241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158511832445105 + 158511832445106.
It is an arithmetic number, because the mean of its divisors is an integer number (158511832445106).
Almost surely, 2317023664890211 is an apocalyptic number.
317023664890211 is a deficient number, since it is larger than the sum of its proper divisors (1).
317023664890211 is an equidigital number, since it uses as much as digits as its factorization.
317023664890211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 53.
The spelling of 317023664890211 in words is "three hundred seventeen trillion, twenty-three billion, six hundred sixty-four million, eight hundred ninety thousand, two hundred eleven".
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