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320004039973 is a prime number
BaseRepresentation
bin1001010100000011011…
…10100010010100100101
31010120222122001112210111
410222001232202110211
520220332013234343
6403001405053021
732055666313522
oct4520156422445
91116878045714
10320004039973
11113792a35642
1252028857171
132423a2bc357
14116b9b9a149
1584cd976c9d
hex4a81ba2525

320004039973 has 2 divisors, whose sum is σ = 320004039974. Its totient is φ = 320004039972.

The previous prime is 320004039959. The next prime is 320004040007. The reversal of 320004039973 is 379930400023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 316561519044 + 3442520929 = 562638^2 + 58673^2 .

It is an emirp because it is prime and its reverse (379930400023) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-320004039973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (320004039923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160002019986 + 160002019987.

It is an arithmetic number, because the mean of its divisors is an integer number (160002019987).

Almost surely, 2320004039973 is an apocalyptic number.

It is an amenable number.

320004039973 is a deficient number, since it is larger than the sum of its proper divisors (1).

320004039973 is an equidigital number, since it uses as much as digits as its factorization.

320004039973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 122472, while the sum is 40.

Adding to 320004039973 its reverse (379930400023), we get a palindrome (699934439996).

The spelling of 320004039973 in words is "three hundred twenty billion, four million, thirty-nine thousand, nine hundred seventy-three".