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32001122113 is a prime number
BaseRepresentation
bin11101110011011010…
…100101111101000001
310001121012202102211221
4131303122211331001
51011014241401423
622411235035041
72212006023052
oct356332457501
9101535672757
1032001122113
1112631887764
12625113ba81
13302cb4311c
141798116729
15c7465de5d
hex7736a5f41

32001122113 has 2 divisors, whose sum is σ = 32001122114. Its totient is φ = 32001122112.

The previous prime is 32001122107. The next prime is 32001122119. The reversal of 32001122113 is 31122110023.

It is a balanced prime because it is at equal distance from previous prime (32001122107) and next prime (32001122119).

It can be written as a sum of positive squares in only one way, i.e., 24885693504 + 7115428609 = 157752^2 + 84353^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32001122113 is a prime.

It is a super-2 number, since 2×320011221132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (32001122119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16000561056 + 16000561057.

It is an arithmetic number, because the mean of its divisors is an integer number (16000561057).

Almost surely, 232001122113 is an apocalyptic number.

It is an amenable number.

32001122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

32001122113 is an equidigital number, since it uses as much as digits as its factorization.

32001122113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 32001122113 its reverse (31122110023), we get a palindrome (63123232136).

The spelling of 32001122113 in words is "thirty-two billion, one million, one hundred twenty-two thousand, one hundred thirteen".