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320012440421 is a prime number
BaseRepresentation
bin1001010100000100011…
…10100101001101100101
31010121000012212100001012
410222002032211031211
520220341141043141
6403002305112005
732056130601602
oct4520216451545
91117005770035
10320012440421
11113797752a63
125202b628605
132423bc70b2b
14116bad456a9
1584ce585ceb
hex4a823a5365

320012440421 has 2 divisors, whose sum is σ = 320012440422. Its totient is φ = 320012440420.

The previous prime is 320012440409. The next prime is 320012440457. The reversal of 320012440421 is 124044210023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 309676668196 + 10335772225 = 556486^2 + 101665^2 .

It is an emirp because it is prime and its reverse (124044210023) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-320012440421 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (320012440021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160006220210 + 160006220211.

It is an arithmetic number, because the mean of its divisors is an integer number (160006220211).

Almost surely, 2320012440421 is an apocalyptic number.

It is an amenable number.

320012440421 is a deficient number, since it is larger than the sum of its proper divisors (1).

320012440421 is an equidigital number, since it uses as much as digits as its factorization.

320012440421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 23.

Adding to 320012440421 its reverse (124044210023), we get a palindrome (444056650444).

The spelling of 320012440421 in words is "three hundred twenty billion, twelve million, four hundred forty thousand, four hundred twenty-one".