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320131003231223 is a prime number
BaseRepresentation
bin100100011001010000100111…
…0101110101010101111110111
31112222111020002001002202122122
41020302201032232222233313
5313430011243311344343
63052510052544150155
7124300462456555502
oct11062411656525767
91488436061082578
10320131003231223
11930048835870a8
122baa364930835b
13109822bb38c202
14590a5cd4ac139
15270251e677068
hex123284ebaabf7

320131003231223 has 2 divisors, whose sum is σ = 320131003231224. Its totient is φ = 320131003231222.

The previous prime is 320131003231079. The next prime is 320131003231243. The reversal of 320131003231223 is 322132300131023.

It is a strong prime.

It is an emirp because it is prime and its reverse (322132300131023) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 320131003231223 - 218 = 320131002969079 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 320131003231192 and 320131003231201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (320131003231243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160065501615611 + 160065501615612.

It is an arithmetic number, because the mean of its divisors is an integer number (160065501615612).

Almost surely, 2320131003231223 is an apocalyptic number.

320131003231223 is a deficient number, since it is larger than the sum of its proper divisors (1).

320131003231223 is an equidigital number, since it uses as much as digits as its factorization.

320131003231223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 320131003231223 its reverse (322132300131023), we get a palindrome (642263303362246).

The spelling of 320131003231223 in words is "three hundred twenty trillion, one hundred thirty-one billion, three million, two hundred thirty-one thousand, two hundred twenty-three".