Base | Representation |
---|---|
bin | 101110100101011101001… |
… | …001101000011001000111 |
3 | 102100001011001000200202111 |
4 | 232211131021220121013 |
5 | 404422242220110401 |
6 | 10450355121121451 |
7 | 450200350163134 |
oct | 56453511503107 |
9 | 12301131020674 |
10 | 3201313441351 |
11 | 102473aa858a3 |
12 | 438529489287 |
13 | 1a2b61cb20bc |
14 | b0d315d758b |
15 | 58418160e51 |
hex | 2e95d268647 |
3201313441351 has 2 divisors, whose sum is σ = 3201313441352. Its totient is φ = 3201313441350.
The previous prime is 3201313441297. The next prime is 3201313441373. The reversal of 3201313441351 is 1531443131023.
3201313441351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3201313441351 - 213 = 3201313433159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3201313541351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600656720675 + 1600656720676.
It is an arithmetic number, because the mean of its divisors is an integer number (1600656720676).
Almost surely, 23201313441351 is an apocalyptic number.
3201313441351 is a deficient number, since it is larger than the sum of its proper divisors (1).
3201313441351 is an equidigital number, since it uses as much as digits as its factorization.
3201313441351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 3201313441351 its reverse (1531443131023), we get a palindrome (4732756572374).
The spelling of 3201313441351 in words is "three trillion, two hundred one billion, three hundred thirteen million, four hundred forty-one thousand, three hundred fifty-one".
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