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3201313441351 is a prime number
BaseRepresentation
bin101110100101011101001…
…001101000011001000111
3102100001011001000200202111
4232211131021220121013
5404422242220110401
610450355121121451
7450200350163134
oct56453511503107
912301131020674
103201313441351
11102473aa858a3
12438529489287
131a2b61cb20bc
14b0d315d758b
1558418160e51
hex2e95d268647

3201313441351 has 2 divisors, whose sum is σ = 3201313441352. Its totient is φ = 3201313441350.

The previous prime is 3201313441297. The next prime is 3201313441373. The reversal of 3201313441351 is 1531443131023.

3201313441351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3201313441351 - 213 = 3201313433159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3201313541351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600656720675 + 1600656720676.

It is an arithmetic number, because the mean of its divisors is an integer number (1600656720676).

Almost surely, 23201313441351 is an apocalyptic number.

3201313441351 is a deficient number, since it is larger than the sum of its proper divisors (1).

3201313441351 is an equidigital number, since it uses as much as digits as its factorization.

3201313441351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 3201313441351 its reverse (1531443131023), we get a palindrome (4732756572374).

The spelling of 3201313441351 in words is "three trillion, two hundred one billion, three hundred thirteen million, four hundred forty-one thousand, three hundred fifty-one".