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32013321123149 is a prime number
BaseRepresentation
bin1110100011101101011101…
…01000100011010101001101
311012100102222101120210001122
413101312232220203111031
513144001240201420044
6152030414450050325
76512612640516062
oct721665650432515
9135312871523048
1032013321123149
11a222856208923
1237104905799a5
1314b2ac675a7c2
147c964b0b6c69
153a7b174dadee
hex1d1daea2354d

32013321123149 has 2 divisors, whose sum is σ = 32013321123150. Its totient is φ = 32013321123148.

The previous prime is 32013321123109. The next prime is 32013321123191. The reversal of 32013321123149 is 94132112331023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31969129515625 + 44191607524 = 5654125^2 + 210218^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32013321123149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32013321123109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16006660561574 + 16006660561575.

It is an arithmetic number, because the mean of its divisors is an integer number (16006660561575).

Almost surely, 232013321123149 is an apocalyptic number.

It is an amenable number.

32013321123149 is a deficient number, since it is larger than the sum of its proper divisors (1).

32013321123149 is an equidigital number, since it uses as much as digits as its factorization.

32013321123149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 32013321123149 in words is "thirty-two trillion, thirteen billion, three hundred twenty-one million, one hundred twenty-three thousand, one hundred forty-nine".