Base | Representation |
---|---|
bin | 1001010100010010111… |
… | …00001011001000100101 |
3 | 1010121022122112221221011 |
4 | 10222021130023020211 |
5 | 20221113130203013 |
6 | 403022310422221 |
7 | 32062130243236 |
oct | 4521134131045 |
9 | 1117278487834 |
10 | 320133444133 |
11 | 113849a8a928 |
12 | 52064061971 |
13 | 2425b059869 |
14 | 116cd04308d |
15 | 84d9ed8c3d |
hex | 4a8970b225 |
320133444133 has 2 divisors, whose sum is σ = 320133444134. Its totient is φ = 320133444132.
The previous prime is 320133444109. The next prime is 320133444203. The reversal of 320133444133 is 331444331023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 263849677569 + 56283766564 = 513663^2 + 237242^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-320133444133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 320133444095 and 320133444104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (320133444233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160066722066 + 160066722067.
It is an arithmetic number, because the mean of its divisors is an integer number (160066722067).
Almost surely, 2320133444133 is an apocalyptic number.
It is an amenable number.
320133444133 is a deficient number, since it is larger than the sum of its proper divisors (1).
320133444133 is an equidigital number, since it uses as much as digits as its factorization.
320133444133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 320133444133 its reverse (331444331023), we get a palindrome (651577775156).
The spelling of 320133444133 in words is "three hundred twenty billion, one hundred thirty-three million, four hundred forty-four thousand, one hundred thirty-three".
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