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32015950013 is a prime number
BaseRepresentation
bin11101110100010011…
…001010000010111101
310001122020122202220102
4131310103022002331
51011032040400023
622412524530445
72212246041065
oct356423120275
9101566582812
1032015950013
111263a195123
1262560b0a25
133032c35328
14179a0963a5
15c75adc628
hex7744ca0bd

32015950013 has 2 divisors, whose sum is σ = 32015950014. Its totient is φ = 32015950012.

The previous prime is 32015949991. The next prime is 32015950049. The reversal of 32015950013 is 31005951023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31670473444 + 345476569 = 177962^2 + 18587^2 .

It is an emirp because it is prime and its reverse (31005951023) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32015950013 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32015952013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16007975006 + 16007975007.

It is an arithmetic number, because the mean of its divisors is an integer number (16007975007).

Almost surely, 232015950013 is an apocalyptic number.

It is an amenable number.

32015950013 is a deficient number, since it is larger than the sum of its proper divisors (1).

32015950013 is an equidigital number, since it uses as much as digits as its factorization.

32015950013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4050, while the sum is 29.

The spelling of 32015950013 in words is "thirty-two billion, fifteen million, nine hundred fifty thousand, thirteen".