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320172550023083 is a prime number
BaseRepresentation
bin100100011001100011111101…
…1000111000110011110101011
31112222122012022111201110200112
41020303013323013012132223
5313431201340301214313
63052541123340124535
7124303463155510532
oct11063077307063653
91488565274643615
10320172550023083
119302046367481a
122baab70323674b
13109861aca37b14
14590c61127d319
152703651d4c8a8
hex12331fb1c67ab

320172550023083 has 2 divisors, whose sum is σ = 320172550023084. Its totient is φ = 320172550023082.

The previous prime is 320172550023077. The next prime is 320172550023101. The reversal of 320172550023083 is 380320055271023.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 320172550023083 - 224 = 320172533245867 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 320172550023083.

It is not a weakly prime, because it can be changed into another prime (320172550023583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160086275011541 + 160086275011542.

It is an arithmetic number, because the mean of its divisors is an integer number (160086275011542).

Almost surely, 2320172550023083 is an apocalyptic number.

320172550023083 is a deficient number, since it is larger than the sum of its proper divisors (1).

320172550023083 is an equidigital number, since it uses as much as digits as its factorization.

320172550023083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 320172550023083 in words is "three hundred twenty trillion, one hundred seventy-two billion, five hundred fifty million, twenty-three thousand, eighty-three".