Search a number
-
+
320191139638417 is a prime number
BaseRepresentation
bin100100011001101100100111…
…1001000110110110010010001
31112222200222022001100202220011
41020303121033020312302101
5313432002423221412132
63052553440124114521
7124305021633601015
oct11063311710666221
91488628261322804
10320191139638417
1193028332a61983
122bab3230995a41
1310987b831692c8
14590d49610c545
152703d8dd71b47
hex123364f236c91

320191139638417 has 2 divisors, whose sum is σ = 320191139638418. Its totient is φ = 320191139638416.

The previous prime is 320191139638369. The next prime is 320191139638463. The reversal of 320191139638417 is 714836931191023.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 292464585747216 + 27726553891201 = 17101596^2 + 5265601^2 .

It is a cyclic number.

It is not a de Polignac number, because 320191139638417 - 27 = 320191139638289 is a prime.

It is not a weakly prime, because it can be changed into another prime (320191139632417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160095569819208 + 160095569819209.

It is an arithmetic number, because the mean of its divisors is an integer number (160095569819209).

Almost surely, 2320191139638417 is an apocalyptic number.

It is an amenable number.

320191139638417 is a deficient number, since it is larger than the sum of its proper divisors (1).

320191139638417 is an equidigital number, since it uses as much as digits as its factorization.

320191139638417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5878656, while the sum is 58.

The spelling of 320191139638417 in words is "three hundred twenty trillion, one hundred ninety-one billion, one hundred thirty-nine million, six hundred thirty-eight thousand, four hundred seventeen".