Base | Representation |
---|---|
bin | 100100011001111111011011… |
… | …1010010001010001000101111 |
3 | 1112222211211120201210201222222 |
4 | 1020303332313102022020233 |
5 | 313433133144123104403 |
6 | 3053024201142425555 |
7 | 124310652061656461 |
oct | 11063766722121057 |
9 | 1488754521721888 |
10 | 320231541613103 |
11 | 930434859044aa |
12 | 2babb0274322bb |
13 | 1098b9215a1bc3 |
14 | 5911409c36131 |
15 | 2704e55cac338 |
hex | 1233fb748a22f |
320231541613103 has 2 divisors, whose sum is σ = 320231541613104. Its totient is φ = 320231541613102.
The previous prime is 320231541613031. The next prime is 320231541613147. The reversal of 320231541613103 is 301316145132023.
Together with previous prime (320231541613031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 320231541613103 - 222 = 320231537418799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (320231541613303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160115770806551 + 160115770806552.
It is an arithmetic number, because the mean of its divisors is an integer number (160115770806552).
Almost surely, 2320231541613103 is an apocalyptic number.
320231541613103 is a deficient number, since it is larger than the sum of its proper divisors (1).
320231541613103 is an equidigital number, since it uses as much as digits as its factorization.
320231541613103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 35.
Adding to 320231541613103 its reverse (301316145132023), we get a palindrome (621547686745126).
The spelling of 320231541613103 in words is "three hundred twenty trillion, two hundred thirty-one billion, five hundred forty-one million, six hundred thirteen thousand, one hundred three".
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