Base | Representation |
---|---|
bin | 11101110110100100… |
… | …000111010000111111 |
3 | 10001201220011100101221 |
4 | 131312210013100333 |
5 | 1011121302341003 |
6 | 22420403214211 |
7 | 2213220034552 |
oct | 356644072077 |
9 | 101656140357 |
10 | 32053949503 |
11 | 12659689764 |
12 | 6266977367 |
13 | 303aa7b434 |
14 | 17a1148699 |
15 | c790e67bd |
hex | 77690743f |
32053949503 has 2 divisors, whose sum is σ = 32053949504. Its totient is φ = 32053949502.
The previous prime is 32053949491. The next prime is 32053949509. The reversal of 32053949503 is 30594935023.
It is a strong prime.
It is an emirp because it is prime and its reverse (30594935023) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32053949503 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 32053949503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32053949509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16026974751 + 16026974752.
It is an arithmetic number, because the mean of its divisors is an integer number (16026974752).
Almost surely, 232053949503 is an apocalyptic number.
32053949503 is a deficient number, since it is larger than the sum of its proper divisors (1).
32053949503 is an equidigital number, since it uses as much as digits as its factorization.
32053949503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 43.
The spelling of 32053949503 in words is "thirty-two billion, fifty-three million, nine hundred forty-nine thousand, five hundred three".
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