Base | Representation |
---|---|
bin | 1110100100111010010000… |
… | …01001000000010011011111 |
3 | 11012111101101210100020120011 |
4 | 13102131020021000103133 |
5 | 13200140210110001033 |
6 | 152101354010504051 |
7 | 6515602443023002 |
oct | 722351011002337 |
9 | 135441353306504 |
10 | 32054551250143 |
11 | a23929357a544 |
12 | 3718478435027 |
13 | 14b6967622256 |
14 | 7cb63cbb7539 |
15 | 3a8c2beaeccd |
hex | 1d27482404df |
32054551250143 has 2 divisors, whose sum is σ = 32054551250144. Its totient is φ = 32054551250142.
The previous prime is 32054551250119. The next prime is 32054551250201. The reversal of 32054551250143 is 34105215545023.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32054551250143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32054551250096 and 32054551250105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32054551260143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16027275625071 + 16027275625072.
It is an arithmetic number, because the mean of its divisors is an integer number (16027275625072).
Almost surely, 232054551250143 is an apocalyptic number.
32054551250143 is a deficient number, since it is larger than the sum of its proper divisors (1).
32054551250143 is an equidigital number, since it uses as much as digits as its factorization.
32054551250143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 32054551250143 its reverse (34105215545023), we get a palindrome (66159766795166).
The spelling of 32054551250143 in words is "thirty-two trillion, fifty-four billion, five hundred fifty-one million, two hundred fifty thousand, one hundred forty-three".
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