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32055862512001 is a prime number
BaseRepresentation
bin1110100100111100101100…
…10011000100100110000001
311012111111210011201020200011
413102132112103010212001
513200200401300341001
6152102132051424521
76515650104406606
oct722362623044601
9135444704636604
1032055862512001
11a2398a6769a29
1237187835b5141
1314b6b161a1243
147cb724dca6ad
153a8ca7176d51
hex1d27964c4981

32055862512001 has 2 divisors, whose sum is σ = 32055862512002. Its totient is φ = 32055862512000.

The previous prime is 32055862511999. The next prime is 32055862512007. The reversal of 32055862512001 is 10021526855023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29218608619776 + 2837253892225 = 5405424^2 + 1684415^2 .

It is an emirp because it is prime and its reverse (10021526855023) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32055862512001 - 21 = 32055862511999 is a prime.

It is a super-2 number, since 2×320558625120012 (a number of 28 digits) contains 22 as substring.

Together with 32055862511999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (32055862512007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16027931256000 + 16027931256001.

It is an arithmetic number, because the mean of its divisors is an integer number (16027931256001).

Almost surely, 232055862512001 is an apocalyptic number.

It is an amenable number.

32055862512001 is a deficient number, since it is larger than the sum of its proper divisors (1).

32055862512001 is an equidigital number, since it uses as much as digits as its factorization.

32055862512001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 40.

The spelling of 32055862512001 in words is "thirty-two trillion, fifty-five billion, eight hundred sixty-two million, five hundred twelve thousand, one".