Base | Representation |
---|---|
bin | 11101111001010101… |
… | …011101110010000111 |
3 | 10001212010122101001111 |
4 | 131321111131302013 |
5 | 1011220203104343 |
6 | 22425143505451 |
7 | 2214323151124 |
oct | 357125356207 |
9 | 101763571044 |
10 | 32100441223 |
11 | 12682953674 |
12 | 627a458287 |
13 | 30475a8a26 |
14 | 17a73ab74b |
15 | c7d22bc9d |
hex | 77955dc87 |
32100441223 has 2 divisors, whose sum is σ = 32100441224. Its totient is φ = 32100441222.
The previous prime is 32100441173. The next prime is 32100441229. The reversal of 32100441223 is 32214400123.
It is a strong prime.
It is an emirp because it is prime and its reverse (32214400123) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32100441223 is a prime.
It is a super-2 number, since 2×321004412232 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32100441194 and 32100441203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32100441229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16050220611 + 16050220612.
It is an arithmetic number, because the mean of its divisors is an integer number (16050220612).
Almost surely, 232100441223 is an apocalyptic number.
32100441223 is a deficient number, since it is larger than the sum of its proper divisors (1).
32100441223 is an equidigital number, since it uses as much as digits as its factorization.
32100441223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 32100441223 its reverse (32214400123), we get a palindrome (64314841346).
The spelling of 32100441223 in words is "thirty-two billion, one hundred million, four hundred forty-one thousand, two hundred twenty-three".
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