Base | Representation |
---|---|
bin | 101110101101100110000… |
… | …100011001110000010101 |
3 | 102100212201010001021200202 |
4 | 232231212010121300111 |
5 | 410043142032001323 |
6 | 10454402240150245 |
7 | 450630051204443 |
oct | 56554604316025 |
9 | 12325633037622 |
10 | 3210053000213 |
11 | 1028415261814 |
12 | 43a168308385 |
13 | 1a39258053c7 |
14 | b15201b5b93 |
15 | 5877a544d28 |
hex | 2eb66119c15 |
3210053000213 has 2 divisors, whose sum is σ = 3210053000214. Its totient is φ = 3210053000212.
The previous prime is 3210053000153. The next prime is 3210053000221. The reversal of 3210053000213 is 3120003500123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2027542470724 + 1182510529489 = 1423918^2 + 1087433^2 .
It is a cyclic number.
It is not a de Polignac number, because 3210053000213 - 228 = 3209784564757 is a prime.
It is a super-3 number, since 3×32100530002133 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3210053000263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605026500106 + 1605026500107.
It is an arithmetic number, because the mean of its divisors is an integer number (1605026500107).
Almost surely, 23210053000213 is an apocalyptic number.
It is an amenable number.
3210053000213 is a deficient number, since it is larger than the sum of its proper divisors (1).
3210053000213 is an equidigital number, since it uses as much as digits as its factorization.
3210053000213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 20.
Adding to 3210053000213 its reverse (3120003500123), we get a palindrome (6330056500336).
The spelling of 3210053000213 in words is "three trillion, two hundred ten billion, fifty-three million, two hundred thirteen", and thus it is an aban number.
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